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How to Fix Container With Most Water Errors

DodaTech Updated 2026-06-26 1 min read

In this tutorial, you'll learn about How to Fix Container With Most Water Errors. We cover key concepts, practical examples, and best practices.

Fix container with most water errors when area calculation uses wrong height (min not max) or pointers move incorrectly.

Quick Fix

Wrong

def water(h):
    mx=0
    for i in range(len(h)):
        for j in range(i+1,len(h)):
            mx=max(mx,(j-i)*min(h[i],h[j]))
    return mx

O(n^2) brute force.

def water(h):
    l=0; r=len(h)-1; mx=0
    while l<r:
        mx=max(mx,(r-l)*min(h[l],h[r]))
        if h[l]<h[r]: l+=1
        else: r-=1
    return mx
[1,8,6,2,5,4,8,3,7] -> 49. O(n) time, O(1) space.

Prevention

Two pointers from both ends. Move the shorter line inward. Area = width * min(height[l], height[r]).

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FAQ

What is container water?

Find max water container. Two-pointer O(n): move shorter side inward.

Why move shorter?

Width decreases each step. To potentially increase area, replace the shorter side.

Proof?

If we move the taller, area limited by shorter side and width decreases. Area can't increase.

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