How to Fix Word Break DP Errors

In this tutorial, you'll learn about How to Fix Word Break DP Errors. We cover key concepts, practical examples, and best practices.

Fix word break dp errors when Trie not used and nested loops check all j instead of word break positions.

Quick Fix

Wrong

def word_break(s,wordDict):
    words=set(wordDict); n=len(s); dp=[False]*(n+1); dp[0]=True
    for i in range(1,n+1):
        for j in range(i):
            if dp[j] and s[j:i] in words: dp[i]=True; break
    return dp[n]

O(n^3) from substring slicing O(n) per check. Works but slow for large inputs.

Right

def word_break(s,wordDict):
    words=set(wordDict); n=len(s); dp=[False]*(n+1); dp[0]=True
    for i in range(1,n+1):
        for w in wordDict:
            if i>=len(w) and dp[i-len(w)] and s[i-len(w):i]==w:
                dp[i]=True; break
    return dp[n]

s='leetcode', words=['leet','code'] -> True. O(n*m*k) where m=words, k=max word len.

Prevention

Iterate over dictionary words instead of all substring endpoints. Prunes unnecessary checks.

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